Acharge q = 3 × 10-6 c of mass m = 2 × 10-6 kg, and speed v = 5 × 106 m/s enters a uniform magnetic field. the mass experiences an acceleration a = 3 × 104 m/s2. what is the minimum magnetic field that would produce such an acceleration?

Magnetic field, B = 0.004 mT

Explanation:

It is given that,

Charge,

Mass of charge particle,

Speed,

Acceleration,

We need to find the minimum magnetic field that would produce such an acceleration. So,

For minimum magnetic field,

B = 0.004 T

or

B = 4 mT

So, the magnetic field produce such an acceleration at 4 mT. Hence, this is the required solution.

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation