A100-w light bulb generates 95w of heat, which is dissipated through a glass bulb that has a radius of 3.0 cm and is 0.50 mm thick. what is the temperature difference between the inner and outer surfaces of the glass? use 'deg c' as your units.

21 °C

Explanation:

Heat generated by bulb in one second, H = 95 W

Radius = 3 cm = 0.03 m, Area = 3.14 x 0.03 x 0.03 = 2.826 x 10^-3 m^2

Thickness, d = 0.5 mm = 0.5 x 10^-3 m

Coefficient of thermal conductivity of glass, K = 0.8 W/mK

Let ΔT be the temperature difference between inner and outer surface.

H = K A ΔT / d

95 = 0.8 x 2.826 x 10^-3 x ΔT / (0.5 x 10^-3)

ΔT = 21 °C

Thus, the temperature difference between the inner and outer surface of the bulb is 21 °C.

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electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia