Determine the stopping distances for an automobile going a constant initial speed of 95 km/h and human reaction time of 0.50 s. for an acceleration a = -3.1 m/s^2 determine the stopping distances fo an automobile going a constant intial speed of 95 km/h and human reaction time of 0.50 s. for an acceleration a = -6.1 m/s^2.

(a) for acceleration a = - 3.1 m/s^2 the stopping distance is 125.43 m.

(b)  for acceleration a = - 3.1 m/s^2 the stopping distance is 70.23 m.

Explanation:

reaction time , t = 0.5 s, u = 95 km/h = 95 x 5 / 18 = 26.38 m/s

(a) a = - 3.1 m/s^2

Let the stopping distance is s.

The distance traveled by the automobile in reaction time t is

s1 = u x t = 26.38 x 0.5 = 13.19 m

The distance traveled before stopping be s2.

v^2 = u^2 - 2 a s2

0 = 26.38^2 - 2 x 3.1 x s2

s2 = 112.24 m

Total stopping distance, s = s1 + s2 = 13.19 + 112.24 = 125.43 m

(b) a = - 6.1 m/s^2

Let the stopping distance is s.

The distance traveled by the automobile in reaction time t is

s1 = u x t = 26.38 x 0.5 = 13.19 m

The distance traveled before stopping be s2.

v^2 = u^2 - 2 a s2

0 = 26.38^2 - 2 x 6.1 x s2

s2 = 57.04  m

Total stopping distance, s = s1 + s2 = 13.19 + 57.04 = 70.23 m

waves moving from a fast medium to a slow medium will experience a reflection as light travels more slowly than red light. total internal reflection occurs when the critical angle is.

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27