(3 points) two forces (f1x = 4.4 n; f1y = 2.1 n) and (f2x = 9.3 n; f2y = −3.8 n) act on an object of mass m = 9.4 kg. the mass is initially at rest. what is the kinetic energy of the mass after 2.6 s?

Iwould sure like to answer your question but i honestly just don’t know

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.

1. electricity2. discharge: )