What is the kinetic energy of a 1450 kg sports car traveling down the road with a speed of 30 m/s?

= 652500J

The easiest way to solve this problem is using the kinetic energy equation:

= mv²/2

A 1450kg sports car traveling down the road at a speed of 30m/s is kinectic energy will be:

= [(1450kg)(30m/s)²]/2 = 1305000kg-m²/s²/2

= 652500J

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!