Two resistors, the first 12 ? and the second 6 2, are connected in parallel to a 48 v battery what is the power dissipated by each resistor? a) p1 144 w, p2-288 w b) p1-162 w, p2-324 w c) p1-180 w, p2-360 w d) p1-192 w, p2 384 w

P₁ = 192 W and P₂ = 384 W

Explanation:

It is given that,

Resistor 1,

Resistor 2,

Voltage, V = 48 V

Power dissipated by resistor 1 is given by :

P₁ = 192 watts

Power dissipated by resistor 2 is given by :

P₂ = 384 watts

So, the power dissipated by both the resistors is 192 watts and 384 watts respectively. Hence, this is the required solution.

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.

answerscientific theory;