Two long, parallel wires are separated by a distance of 2.2 cm. the force per unit length that each wire exerts on the other is 3.6 × 10^-5 n/m, and the wires repel each other. the current in one wire is 0.52 a. what is the magnitude of the current in the second wire? (give your answer in decimal using "a" (ampere) as unit)

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward