The angular velocity of the rear wheel of a stationary exercise bike is 5.40 rad/s at time t = 0.000 sec, and its angular acceleration is constant and equal to 1.50 rad/s^2. a particular spoke coincides with the +x axis at time t = 0.000 sec. (a) what angle (in rev) does this spoke make with the +x axis at time t = 4.00 s? (b) what is the angular velocity (rev/s) at this time?

The angle and angular velocity at time 4.00 are 5.35 rev and 1.81 rev/s.

Explanation:

Given that,

Angular velocity = 5.40 rad/s

Time t = 0.000 sec

Angular acceleration = 1.50 rad/s^2

(a). We need to calculate the angle at time t = 4.00 s

Using formula for angle

Where, =angular velocity

=angular acceleration

t = time

Put the value into the formula

(b). We nee to calculate the angular velocity at 4.00 s

Using formula of angular velocity

Hence, The angle and angular velocity at time 4.00 are 5.35 rev and 1.81 rev/s.