Show that, in a li. h. nonconducting region rather 'where 0 and j, 0, the fields e and b can be found completely from a vector potential, that is, ф-const. (zero is usually chosen). what two first. equations determine a? etiza- time, m oten- 22-7 consider a region where p,-0, j, -0, =0, while p is a given function of posi- the tion and time. show that (22-4) and (22-5) nd can be satisfied and the electromagnetic field ob- such that a l from a single vector

the answer would be 32*f

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft