An object of inertia 0.5kg is hung from a spring, and causes it to extend 5cm. in an elevator accelerating downward at 2 m/s^2 , how far will the spring extend if the same object is suspended from it? draw the free body diagrams for both the accelerating and non-accelerating situations.

3.98cm

Explanation:

given data

mass of object=0.5kg

intial extension=5 cm

elevator acceleration=2 m/

From FBD of intial position

Kx=mg

K=

k=98.1 N/m

From FBD of second situation

mg-k=ma

k=m(g-a)

=

=3.98cm

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