Physics, 12.07.2019 23:20 jeremytheprimerapper
A0.350 kg iron horseshoe that is initially at 600°c is dropped into a bucket containing 21.9 kg of water at 21.8°c. what is the final equilibrium temperature (in °c)? neglect any heat transfer to or from the surroundings. do not enter units.
Answers: 1
![m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]](/tpl/images/0082/6549/b0e58.png)
= mass of iron horseshoe = 0.35 kg = 350 g (1kg=1000g[/tex]
= mass of water = 21.9 kg = 21900 g
= final temperature = ?
= temperature of iron horseshoe = 
= temperature of water = 
= specific heat of iron horseshoe = 
= specific heat of water = 
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](/tpl/images/0082/6549/09236.png)
![350\times 0.450\times (T_{final}-600)^0C=-[21900g\times 4.184\times (T_{final}-21.8)]](/tpl/images/0082/6549/b6424.png)
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A0.350 kg iron horseshoe that is initially at 600°c is dropped into a bucket containing 21.9 kg of w...
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