Asingly charged ion of 7li (an isotope of lithium which lost only one electron) has a mass of 1.16 ×10^-26 kg. it is accelerated through a potential difference of 224 v and then enters a magnetic field with magnitude 0.724 t perpendicular to the path of the ion. what is the radius of the ion’s path in the magnetic field? (give your answer in decimal using "mm"(millimeter) as unit)

Explanation:

It is given that,

Mass of lithium,

It is accelerated through a potential difference, V = 224 V

Uniform magnetic field, B = 0.724 T

Applying the conservation of energy as :

q is the charge on an electron

v = 78608.58 m/s

To find the radius of the ion's path in the magnetic field. The centripetal force is balanced by the magnetic force as :

r = 0.0078 meters

So, the radius of the path of the ion is 0.0078 meters. Hence, this is the required solution.

1/0.14nm = 10^10/1.4 a lot