Apulley has a moment of inertial of 0.85kg m about an axle and a radius of 170mm. the string is wrapped around the pulley exerts a constant force of magnitude 32n. determine the angular acceleration of the pulley. find the rotational speed of the pulley at t = 2s. how many revolutions did the pulley make during this time?

The no of revolutions is 2.032 revolution.

Explanation:

Given that,

Moment of inertia = 0.85 Kgm²

Radius = 170 mm

Force = 32 N

Time =  2s

We need to calculate the angular acceleration

Using formula of torque

Where, F = force

r = radius

I = moment of inertia

Put the value into the formula

We need to calculate the rotational speed

Using equation of angular motion

We need to calculate the angular position

Using equation of angular motion

We need to calculate no of revolutions

Hence, The no of revolutions is 2.032 revolution.

i think the answer is a, hope this is right, that would be my best guess.