If the specific heat of water is 1.0 calorie/gram°c, how many calories are required to raise 500 grams of water 10.0°c?
510 cal
5,000 cal
50 cal
501 cal

5,000 cal

Explanation:

q = m C ΔT

where q is heat, m is mass, C is specific heat, and ΔT is change in temperature.

q = (500 g) (1.0 cal/g/°C) (10.0°C)

q = 5,000 cal

if they have a finite resultant

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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