Use hooke's law to determine the work done by the variable force in the spring problem. a force of 250 newtons stretches a spring 30 centimeters. how much work is done in stretching the spring from 30 centimeters to 60 centimeters? n-cm

112.5 J

Explanation:

F = 250 N, x = 30 cm = 0.3 m

Let the spring constant be K.

By using the Hooke's law

F = k x

250 = k x 0.3

k = 833.3 N / m

xi = 30 cm = 0.3 m, xf  60 cm = 0.6 m

Work done = 1/2 k (xf^2 - xi^2)

Work done = 0.5 x 833.33 x (0.6^2 - 0.3^2)

Work done = 112.5 J

answer: decibel

explanation: