Two identical loudspeakers are some distance apart. a person stands 5.80 m from one speaker and 3.90 m from the other. what is the fourth lowest frequency at which destructive interference will occur at this point? the speed of sound in air is 343 m/s.

f = 632 Hz

Explanation:

As we know that for destructive interference the path difference from two loud speakers must be equal to the odd multiple of half of the wavelength

here we know that

given that path difference from two loud speakers is given as

now we know that it will have fourth lowest frequency at which destructive interference will occurs

so here we have

now for frequency we know that

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