Ameteor is falling towards the earth. if the mass and radius of the earth are 6×10^24 kg and 6.4×10^6 m respectively. find the hieght of the meteor where its acceleration due to gravity is 4m/s^2

3.6×10⁶ m

Explanation:

Newton's law of universal gravitation states that the force between two masses is:

F = GMm / r²

where G is the universal constant of gravitation (6.67×10⁻¹¹ m³/kg/s²),

M is the mass of one object

m is the mass of the other object,

and r is the distance between the center of masses of the objects.

The force acting on the meteor is:

∑F = ma

GMm / r² = ma

GM / r² = a

Given M = 6×10²⁴ kg and a = 4 m/s²:

(6.67×10⁻¹¹ m³/kg/s²) (6×10²⁴ kg) / r² = 4 m/s²

r = 10⁷ m

The distance from the meteor to the center of the Earth is 10⁷ m.  We want to know what the height of the meteor is (distance to the surface of the Earth).  So we need to subtract the Earth's radius.

h = 10⁷ m − 6.4×10⁶ m

h = 3.6×10⁶ m

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force