Physics, 06.07.2019 16:10 ochoanene822

Aspring-loaded gun, fired vertically, shoots a marble 9.0 m straight up in the air. what is the marble's range if it is fired horizontally from 1.8 m above the ground?

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Answer from: winnie45

The range of the marble if it is fired horizontally is 8.10 meters.

Given the following data:

Vertical distance = 9.0 meters.Horizontal distance = 1.8 meter.

To calculate the range of the marble if it is fired horizontally:

How to calculate the vertical speed.

We would determine the vertical speed of the marble fired vertically by the spring-loaded gun through this formula:

$V=\sqrt{2gh} \\\\V=\sqrt{2 \times 9.8 \times 9.0}\\\\V=\sqrt{176.4}$

V = 13.28 m/s.

Next, we would calculate the time taken to reach the maximum height:

$t=\sqrt{\frac{2h}{g} } \\\\t=\sqrt{\frac{2 \times 1.8}{9.8} }\\\\t=\sqrt{0.3674}$

Time, t = 0.61 seconds.

For the marble's range:

$Range = 13.28 \times 0.61$

Range = 8.10 meters.

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Answer from: gshreya2005

$d = 13.3 \times 0.61 = 8.06 m$

Explanation:

If a marble is shot straight up in the air then the maximum height above the ground is given as 9 m

so here we will have

$mgh = \frac{1}{2}mv^2$

$v = \sqrt{2gh}$

$v = \sqrt{2(9.8)(9)} = 13.3 m/s$

now the same marble is shot horizontally so the speed will be same

now the height from which it is shot is given as 1.8 m

so time taken by it to reach the ground is given as

$y = \frac{1}{2}gt^2$

$1.8 = \frac{1}{2}(9.8) t^2$

t = 0.61 s

now the distance moved by the marble is given as

distance = speed x time

$d = 13.3 \times 0.61 = 8.06 m$

Answer from: Quest

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

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Aspring-loaded gun, fired vertically, shoots a marble 9.0 m straight up in the air. what is the marb...

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