Acircular swimming pool has a diameter of 8 meters. the sides are 3 meters high and the depth of the water is 1.5 meters. how much work is required to pump all of the water over the side? your answer must include the correct

Work done = 2218.97 kJ

Explanation:

Work = Force x Displacement.

Force = Weight of water.

Weight of water = Mass of water x Acceleration due to gravity.

Mass of water = Volume of water x Density of water.

Volume of water = Base area of swimming pool x Depth of water.

Base area of swimming pool

Depth of water = 1.5 m

Volume of water

Mass of water = 75.40 x 1000 = 75400 kg

Weight of water = 75400 x 9.81 = 739656 N

Work done = 739656 x 3 = 2218.97 kJ

a.metals can become magnetic if they have many spinning electrons that create magnetic fields.d.only some metals are attracted by magnets; these metals are called ferromagnetic.

d.wrapping an insulated wire around a metal with ferromagnetic properties and applying an electric current.

grav potential energy