Auniform ladder 5.0 m long rests against a frictionless, vertical wall with its lower end 3.0 m from the wall. the ladder weighs 160 n. the coefficient of static friction between the foot of the ladder and the ground is 0.40. a man weighing 740 n climbs slowly up the ladder.
what is the actual frictional force when the man has climbed 1.0 m along the ladder?
how far along the ladder can the man climb before the ladder starts to slip?

Ithink the answer for this is: an electromagnet is a magnet  with a soft metal core.

The figure is missing but we can answer anyway.the correct answer is "releasing the string". in fact, when the person is holding the bow and the arrow, the kinetic energy of the arrow is still zero (because the arrow is not moving). the moment the arrow is released, it acquires a velocity v, so its kinetic energy will become different from zero: where m is the mass of the arrow and v its velocity.  all the other options, instead, do not increase the kinetic energy of the system: -  pulling farther back on the string : this will just increase the elastic potential energy of the system-  holding the arrow higher: this will increase the gravitational potential energy of the system (which is given by u=mgh, where h is the height above the ground)-  decreasing the mass of the arrow: this will decrease the gravitational potential energy of the system (which is given by u=mgh, where m is the mass)