Physics, 05.07.2019 18:20 makayladurham19

5.90. a force is applied to a block to move it up a 30° incline. the incline is frictionless. if f = 65.0 n and m = 5.00 kg , what is the magnitude of the acceleration of the block? enter your answer in units of m/s^2m/s 2 , without units, to the nearest hundredth.

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Acceleration is defined as the rate of change of the velocity of the body. Its unit is m/sec².The magnitude of the acceleration of the block will be 6.35 m/sec².

What is the friction force?

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

Mathematically it is defined as the product of the coefficient of friction and normal reaction.

On resolving the given force and accelertaion in the different components and balancing the equation gets.Components in the x-direction.

The given data in the problem,

F is the applied force =65 N

Θ is the angle of inclined plane=30°

m is the mass of the block= 5 kg

We need to find the acceleration of the block in the x-direction

$\rm F_x=ma_x\\\\\rm F_x=Fcos\theta-mgsin\theta\\\\\rm Fcos\theta-mgsin\theta=ma_x\\\\\rm a_x=\frac{Fcos\theta-mgsin\theta}{m}\\\\ \rm a_x=\frac{65\timescos30^0-mgsin30^0}{5} \\\\\rm a_x=6.35 m/sec^2$

Hence the magnitude of the acceleration of the block will be 6.35 m/sec².

To know more about friction force refer to the link;

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5.90. a force is applied to a block to move it up a 30° incline. the incline is frictionless. if f =

Answer from: jessezarate4513

The acceleration of the block is 6.35 m/s².

Explanation:

It is given that,

A force is applied to a block to move it up a 30° incline. The applied force is, F = 65 N

Mass of the block, m = 5 kg

We need to find the acceleration of the block. From the attached figure, it is clear that.

F_x=ma_x

$F\ cos\theta-mg\ sin\theta=ma_x$

$a_x=\dfrac{F\ cos\theta-mg\ sin\theta}{m}$

$a_x=\dfrac{65\ N\ cos(30)-5\ kg\times 9.8\ m/s^2\ sin(30)}{5\ kg}$

$a_x=6.35\ m/s^2$

So, the acceleration of the block is 6.35 m/s². Hence, this is the required solution.

Answer from: Quest

the answer is 3.1 his answer is wrong mines is right

Answer from: Quest

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia

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5.90. a force is applied to a block to move it up a 30° incline. the incline is frictionless. if f =...