Acylinder which is in a horizontal position contains an unknown noble gas at 4.63 × 104 pa and is sealed with a massless piston. the piston is slowly, isobarically moved inward 0.163 m, while 1.95 × 104 j of heat is removed from the gas. if the piston has a radius of 0.272 m, calculate the change in internal energy of the system.

The change in internal energy of the system is -17746.78 J

Explanation:

Given that,

Pressure

Remove heat

Radius = 0.272 m

Distance d = 0.163 m

We need to calculate the internal energy

Using thermodynamics first equation

...(I)

Where, dU = internal energy

Q = heat

W = work done

Put the value of W in equation (I)

Where, W = PdV

Put the value in the equation

Hence, The change in internal energy of the system is -17746.78 J

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