The windpipe of a typical whooping crane is about 4.6 ft long. what is the lowest resonant frequency of this pipe, assuming that it is closed at one end? assume a temperature of 33â°c. ans in hz

Frequency, f = 481.8 Hz

Explanation:

Given that,

Length of windpipe, l = 4.6 ft = 0.182 m

We need to find the lowest resonant frequency of this pipe at 33 degrees Celcius. Firstly, we will find the speed of sound at 33 degrees Celcius as :

v = 350.8 m/s

At resonance, wavelength is equal to 4 times length of pipe i.e.

λ = 4 l

We need that,

f = 481.8 Hz

So, the resonant frequency of the windpipe is 481.8 Hz. Hence, this is the required solution.

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