Using magnetostatic pressure on a small patch of a uniform surface current of density k [current/width] why can we not analogous argument as griffiths did for electrostatic pressure, derive a formula for an regard this pressure [force/area] as being able to do work on the moving charges?

Astone is thrown with a speed v0 and returns to earth, as the drawing shows. ignore friction and air resistance, and consider the initial and final locations of the stone. which one of the following correctly describes the change δpe in the gravitational potential energy and the change δke in the kinetic energy of the stone as it moves from its initial to its final location? options a.δpe = 0 j and δke = 0 j b.δpe is positive and δke is negative c.δpe = 0 j and δke is positive d.δpe is negative and δke is positive e.δpe = 0 j and δke is negative