Astring of length l= 1.2 m and mass m = 20g is under 400 n of tension, its two ends are fixed. a. how many nodes will you see in the 5th harmonic.
i. 4
ii. 5
iii. 6
iv. 7
v. none of the above.

(iii) 6

Explanation:

Part a)

Since it is given that both ends are fixed and it is vibrating in 5th harmonic

So here it will have 5 number of loops in it

so we can draw it in following way

each loop will have 1 antinode and two nodes which means number of nodes is one more than number of anti-nodes

So there are 5 loops which means it will have 5 antinodes

and hence there will be 6 nodes in it

so correct answer will be

(iii) 6

c. 7/3

step-by-step explanation:

a rational number is like pi- it is a repeating decimal.

a. is -1.8

b. 2.236068

c. 2.3333333333333333333

d.   is 3

i hope that ! =)

close lines strong magnet less close weaker