Arobot car drives off a cliff that is 11 meters above the water below. the car leaves the cliff horizontally with some initial speed and travels down to the water. the car hits the water a distance of 15 meters from the base of the cliff (it has no air resistance as it falls). what was the driving speed of the car? g =< 0,-9.8,0> n/kg.

Driving speed of the car = 10 m/s

Explanation:

The car hits the water a distance of 15 meters from the base of the cliff.

Horizontal displacement = 11 m

A robot car drives off a cliff that is 11 meters above the water below.

Vertical displacement = 11 m

We have

     s = ut + 0.5 at²

     11 = 0 x t + 0.5 x 9.81 x t²

      t = 1.50 s

So the car moves 15 meters in 1.50 seconds.

     Velocity

Driving speed of the car = 10 m/s

c. convergent boundary.

explanation: