What is the minimum index of refraction of a clear material if a minimum thickness of 121 nm , when laid on glass, is needed to reduce reflection to nearly zero when light of 675 nm is incident normally upon it? assume that the film has an index less than that of the glass.

Explanation:

Since the reflection is nearly zero intensity

so here we will say that the reflected light must show destructive interference

so here we have

here we have

t = 121 nm

now from above equation we have

colorectal cancer may also develop from areas of abnormal cells in the lining of the colon or rectum. this area of abnormal cells is called dysplasia and is more commonly seen in people with certain inflammatory diseases of the bowel such as crohn's disease or ulcerative colitis.

answer: option c.

explanation: