Acopper (shear modulus 4.2 x 1010 n/m2) cube, 0.242 m on a side, is subjected to two shearing forces, each of magnitude f = 3.07 x 10 6 n (see the drawing). find the angle (in degrees), which is one measure of how the shape of the block has been altered by shear deformation.

The angle is 0.00124°.

Explanation:

Given that,

Shear modulus

One side of copper = 0.242 m

Shearing forces

We calculate the angle

Using formula of shear modulus

F = force

A = area

S = shear modulus

Put the value into the formula

Hence, The angle is 0.00124°.

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