Awater distribution system is composed of three sections, by which the water flows at 10 1.325 kpa and 25%. in section i , the water flows through a mass flow rate of m1 20.0 kg/s. in section 2 the flow occurs in a cross-sectional area of 0.003m2. while in section 3 the fluid in question flows with a volumetric flow rate q3 0.06 m3 s. it is known that sections 1 and 2 are inlet nozzles discharging in section 3. it is also known that the entire process is carried out in a steady state. considering the above, determine the mass flow rate, in kg/s, and the flovw velocity, in m/s at the entrance of section 2, considering the fluid density 997 kg/m3

ι вєℓιєνє ιт ιѕ тнє fιяѕт ¢нσι¢є(α.)

нє ѕнσυℓ∂ ѕмιℓє ρσℓιтℓу αи∂ ѕρєαк тσ тнє ρєяѕσи ωнσ ιѕ ιитєяяυριиg αfтєя тнє ∂ιѕ¢υѕѕισи

нσρє ι ¢συℓ∂ нєℓρ.

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.