Physics, 02.07.2019 22:20 aliopqwas

Asystem can have a nonzero velocity while the net external force on it is zero. describe such a situation.

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Answer from: s77969

Explanation:

According to the Newton's second law of motion

F = m a

where, f be the force , m be the mass and a be the acceleration.

According to the question, F = 0

So, a = 0

a = v - u / t

So, v - u = 0

v = u

That means the velocity is constant.

If a body is moving with constant velocity, its acceleration is zero but velocity is non zero.

For example, a car is moving on a straight track with constant speed and in the same direction is the example in which velocity is non zero but acceleration is zero.

Answer from: jonnycampbell223

Yes, a system can have a non-zero velocity.

Explanation:

When the net force is zero, applying Newton's second law, the net force is:

F = mass * acceleration

Acceleration can be defined as the change in velocity over time. Since the net force is zero, it also means that the acceleration is zero, since the speed is not changing, but the speed is not equal to zero. If a body moves with a constant velocity other than zero, this body has a net force equal to zero.

Answer from: Quest

electromagnetic waves travel through space with vacuums. give me brainliest if right.

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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Asystem can have a nonzero velocity while the net external force on it is zero. describe such a situ...

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