A1240-kg car is traveling with a speed of 15.0 m/s. what is the magnitude of the horizontal net force that is required to bring the car to a halt in a distance of 31.8 m?

Force required is 4387 N in the opposite direction of motion.

Explanation:

We have equation of motion v² = u² + 2as

      v = 0m/s , u = 15 m/s, s = 31.8 m

  Substituting

         0² = 15² + 2 x a x 31.8

          a = -3.54 m/s²

So, deceleration = 3.54 m/s²

Force = Mass x Acceleration

          = 1240 x -3.54 = -4387 N

So force required is 4387 N in the opposite direction of motion.

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.

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