Physics, 29.06.2019 05:20 janayflowers042

Suppose the mass of a fully loaded module in which astronauts take off from the moon is 10,000 kg. the thrust of its engines is 30,000 n. (a) calculate its the magnitude of acceleration in a vertical takeoff from the moon. (b) could it lift off from earth? if not, why not? if it could, calculate the magnitude of its acceleration.

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Answer from: lilyrockstarmag

Acceleration is the rate of change of velocity. The acceleration of the module is 1.365 m/s².

Given to us

Mass of the Module = 10,000 kg

The thrust of the engine, Fₓ = 30,000 N

A.)

We know in order to lift the module the thrust produced by the engine must be greater than the gravitational pull by the module. therefore,

$F_{N} = F_x - W$

where W is the weight of the moon,

$F_{N} = F_x - (m\times g_{moon})$

Also, the acceleration on the moon is 1/6 of the acceleration on the earth,

$F_{N} = 30,000- (10,000\times \dfrac{9.81}{6})\\F_N = 13,650\ N$

We know that force is the product of mass and acceleration, therefore,

$F_N = m \times a\\\\13,650 = 10,000 \times a\\\\a = 1.365 m/s^2$

Hence, the acceleration of the module is 1.365 m/s².

B.)

If we need to lift the module on earth, we need a thrust that is greater than the weight of the module,

$Weight = mass \times acceleration\\W = 10,000 \times 9.81\\W = 98,100\ N$

As the weight of the module is greater than the thrust produced by engines. therefore, the module can not take off from the earth.

Learn more about Acceleration:

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Answer from: davidoj13

Part a)

a = 1.37 m/s/s

Part b)

since the force of gravity is more than the thrust force of rocket so it will not lift off the surface of Earth

Explanation:

Part a)

Net force on the Module due to thrust of engine is given as

F = 30,000 N

now net force while is ejected out of the surface of moon is given as

$F_{net} = F - F_g$

here we know that

$F_g = mg_{moon}$

where we have

$g_{moon} = \frac{g}{6}$

$F_{net} = 30,000 - (10000)(\frac{9.8}{6})$

$F_{net} = 13666.67 N$

now the acceleration of the module on the moon is

$a = \frac{F_{net}}{m}$

$a = \frac{13666.67}{10,000} = 1.37 m/s^2$

Part b)

Now on the surface of earth the force of gravity on the module is given as

F_g = mg

$F_g = 10,000 \times 9.8$

F_g = 98000 N

since the force of gravity is more than the thrust force of rocket so it will not lift off the surface of Earth

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

Answer from: Quest

uranium fissions/breaks up giving out energy and neutrons

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