If at a particular instant and at a certain point in space the electric field is in the +x-direction and has a magnitude of 4.50 v/m , what is the magnitude of the magnetic field of the wave at this same point in space and instant in time?

1.5 x 10^-8 Tesla

Explanation:

E = 4.5 V/m

The relation between electric field and the magnetic field in electromagnetic wave is given by

c = E / B

Where, c be the velocity of light in vacuum, e be the electric field and B be the magnetic field

B = E / c

B = 4.5 / ( 3 x 10^8)

B = 1.5 x 10^-8 Tesla

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

when the use of electricity burdens the fuse and miniarure circuit beakers and there is a possibility of a fuse then they automatically cut off the electricity supply to your homes and after you fix the problem u jzt switch it on and it continues the supply of electricity to ur homes