Two simple pendulums are in two different places. the length of the second pendulum is 0.4 times the length of the first pendulum, and the acceleration of gravity experienced by the second pendulum is 0.9 times the acceleration of gravity experienced by the first pendulum. determine the comparison of the frequency of the first pendulum to the second pendulum. a) 2/3. b) 3/2 (5 marks) c) 4/9. d) 9/4

Explanation:

The frequency of a simple pendulum is given by:

where

g is the acceleration of gravity

L is the length of the pendulum

Calling the length of the first pendulum and the acceleration of gravity at the location of the first pendulum, the frequency of the first pendulum is

The length of the second pendulum is 0.4 times the length of the first pendulum, so

while the acceleration of gravity experienced by the second pendulum is 0.9 times the acceleration of gravity experienced by the first pendulum, so

So the frequency of the second pendulum is

Therefore the ratio between the two frequencies is

c.the charges if the proton and electron and gravity

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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