0.5000 kg of water at 35.00 degrees celsius is cooled, with the removal of 6.300 e4 j of heat. what is the final temperature of the water? specific heat capacity of water is 4186 j/(kg c°).

=30.22°C

Explanation:

The enthalpy change made the water to cool.

Enthalpy change = MC∅ where M is the mass of the water, C is the specific heat capacity of water and ∅ the temperature change.

ΔH=MC∅

∅=ΔH/MC

=(6.3×10⁴J)/(0.5kg×4186J/(kg°C))

=30.1

Final temperature = 35.00°C-30.1°C

=4.9°C

Explanation:

Given that,

Mass of water is m= 0.5kg

At initial temperature of θi = 35°C

Specific heat capacity of water

c = 4186J/kg•C

Heat H = 6.3 × 10⁴ J

Final temperature θf =?

Using the heat formulas

H = mc∆θ

H = mc(θf-θi)

Where,

H is heat

m is mass of substance

θi is initial temperature

θf is final temperature

Since it is cooled

H = mc(θi - θf)

6.3×10⁴ = 0.5×4186(35—θf)

63000/(0.5×4186) = (35-θf)

30.1 = 35-θf

-θf = 30.1-35

-θf = -4.9°C

θf = 4.9°C

The final temperature is 4.9°C

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

a.metals can become magnetic if they have many spinning electrons that create magnetic fields.d.only some metals are attracted by magnets; these metals are called ferromagnetic.

d.wrapping an insulated wire around a metal with ferromagnetic properties and applying an electric current.