Amonoatomic ideal gas undergoes an isothermal expansion at 300 k, as the volume increased from 0.010 m^3 to 0.040 m^3. the final pressure is 130 kpa. what is the change in the internal (thermal) energy of the gas during this process? (r=8.31 j/mol . k) a. 0.0 kj b. 3.6 kj c. 7.2 kj d.-3.6 kj e.-7.2 kj

A) 0.0 kJ

Explanation:

Change in the internal energy of the gas is a state function

which means it will not depends on the process but it will depends on the initial and final state

Also we know that internal energy is a function of temperature only

so here the process is given as isothermal process in which temperature will remain constant always

here we know that

now for isothermal process since temperature change is zero

so change in internal energy must be ZERO

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .