Aproton starting from rest travels through a potential of 1.0 kv and then moves into a uniform 0.040-t magnetic field. what is the radius of the proton's resulting orbit? (mproton = 1.67 × 10-27 kg, e = 1.60 × 10-19 c)

The radius of the proton orbit is 0.114m

When the proton travels through the potential V it gains kinetic energy given below:

Now, a moving charge under magnetic field B undergoes circular motion due to the magnetic force being perpendicular to the velocity of the charge, given by:

the radius of the orbit is 0.114m

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Radius = 0.11 m

Explanation:

To find the speed of the proton we know that

here we have

now we have

now we have

Now for the radius of the circular motion of charge we know

resonant frequency

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