Hubble’s law states that the velocity of a galaxy is equal to h0d. substitute this value into the time equation, and simplify the equation. use h to represent the hubble constant.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j

no

explanation:

no i dont know how to solve this you should probably try to google the answer