Auniform metal bar is 5.00 m long and has mass 0.300 kg. the bar is pivoted on a narrow support that is 2.00 m from the left-hand end of the bar. what distance x from the left-hand end of the bar should an object with mass 0.900 kg be suspended so the bar is balanced in a horizontal position?

we have that from the Question, it can be said that   distance x from the left-hand end of the bar is

x=1.834m

From the Question we are told

A uniform metal bar is 5.00 m long and has mass 0.300 kg. The bar is pivoted on a narrow support that is 2.00 m from the left-hand end of the bar. What distance x from the left-hand end of the bar should an object with mass 0.900 kg be suspended so the bar is balanced in a horizontal position?

Generally the equation for Balanced torque is mathematically given as

T=0.3/5*3

T=0.18kg

Therefore  

The clockwise torque is

T_c=0.18*1.5g

And

The anti-clockwise torque is

T=0.3/5*2g

T=0.12

Hence

0.18*1.5g=0.3/5*2g+0.9kxg

Therefore

x=1.834m

Therefore

distance x from the left-hand end of the bar is

x=1.834m

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The position of the 0.9 kg mass to balance the metal bar is 1.83 m.

The given parameters;

The center of gravity of the metal bar = 2.5 m

A sketch of weight on the metal bar;

|-----------2 m-----------|--- 0.5 m-----|

0---------------------------Δ--------------------------------------------------

   P ↓|-------- x----------|                     ↓

    0.9 kg                                   0.3 kg

Take moment about the pivot point;

0.9x = 0.3(0.5)

0.9x = 0.15

2 m - P = 0.167 m

P = 2m - 0.167 m

P = 1.83 m

Thus, the position of the 0.9 kg mass to balance the metal bar is 1.83 m.

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the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force