Atraveler pulls on a suitcase strap at an angle 36 above the horizontal with a force of friction of 8 n with the floor. if 752 j of work are done by the strap while moving the suitcase a horizontal distance of 15 m, what is the tension in the strap?

71.8 N

Explanation:

T = Tension force in the strap

W = net work done = 752 J

f = force of friction = 8 N

d = displacement = 15 m

θ = angle between tension force and horizontal displacement = 36 deg

work done by frictional force is given as

W' = - f d

Work done by the tension force is given as

W'' = T d Cos36

Net work done is given as

W = W' + W''

W = T d Cos36 - f d

752 = T (15) Cos36 - (8) (15)

T = 71.8 N

i think they are all correct

explanation:

they seem good

nah.   i'm just sleepy.