Astone is thrown straight up from the edge of a roof, 925 feet above the ground, at a speed of 20 feet per second. remembering that the acceleration due to gravity is -32 feet per second squared, how high is the stone 6 seconds later?

469 feet

Explanation:

This problem is a good example of Vertical motion, where the main equation for this situation is:

(1)

Where:

is the height of the stone at 6s (the value we want to find)

is the initial height of the stone

is the initial velocity of the stone

is the time  at which we need to find the height

is the acceleration due to gravity

Having this clear, let's find from (1):

(2)

Finally:

This is the height of the stone at t=6s

That would be the corect answer hope this

Answerthe force between the charges will be  f/9 (one-ninth of force f)explanationcoulomb's law relates the magnitudes  two point charges q₁ and q₂, the distance, r, between the charges, and the electrostatic force, f, between the two charges:     k represents coulomb's constant, k = 8.99×10⁹ n·m²/c².note that if we have r = 3r, then