The man fires an 80 g arrow so that it is moving at 80 m/s when it hits and embeds in a 8.0 kg block resting on ice. how far will the block slide on the ice before stopping? a 7.1 n friction force opposes its motion.

The block will be slide 0.36 m on the ice.

Explanation:

Given that,

Mass of arrow m₁= 80 g

Velocity of arrow u₁= 80 m/s

Mass of block m₂= 8.0 kg

Force F = 7.1 N

Using conservation of momentum

The work done is equal to the change in kinetic energy

We know that,

The work is defined as,

Hence, The block will be slide 0.36 m on the ice.

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get

b.

hope this : )