Two objects of different mass start from rest, are pulled by the same magnitude net force, and are moved through the same distance. the work done on object 1 is 900 j. after the force has pulled each object, object 1 moves twice as fast as object 2. how much work is done on object 2?
C is the correct answer but the best possible answer is that work is done when a force is imposed on an object and the object moves in the same direction as the force
Hope this helps!
C. No work is done if the direction of motion is perpendicular to the force.
We know that work is the dot product of force and displacement.
Let's take the angle between the force and the displacement = θ
W= F . d cosθ
F=Force , d=Displacement
If θ = 0° then W= F.d
If θ = 90° then W= 0
So we can say that when force is perpendicular to the displacement then the work done by force will be zero.
Therefore the answer is C.
energy is added to it
I think its b, but not so sure
dont sue me if im wrong please
It's true, that other person was incorrect.
No work is done if the direction of motion is perpendicular to the force.
The speed of a satellite in a circular orbit changes in direction but not in magnitude, that is why it remains constant, but its velocity is changing along the time. Now, in this case, the direction of the motion is perpendicular to the acting force, which is the centripetal force, and knowing that the work is proportional to the scalar product of force and displacement, no work is done on the satellite.
I hope it helps you!
work=F*d where F and d are in the same direction.
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