Which statement correctly describes the current in a circuit that is made up of any two resistors connected in parallel with a battery? a. the current in the battery and in each resistor is the same b. the current the battery equals to the sum of the currents in the resistors c. the current in the battery is less than the current in either resistor d. the current in the battery equals to the product of the currents in the resistors
Current in the battery will be 11.7 A
We have given that the there is parallel circuit with three different branches.
Current in each branch is , ,
We have to find the current I in the battery
It is known that in parallel circuit current is sum of current in each branches
So current in the battery will be equal to
Therefore current in the battery will be 11.7 A
D.The current in the battery and in each resistor is the same
In a series circuit, all the components of the circuit are connected in the same branch of the circuit - this means that the current flowing through each component is the same. Therefore, the current in the battery is equal to the current flowing through each resistor.
The total resistance of a series of n resistors is given by the sum of the individual resistances:
On the contrary, when the components are connected in parallel to the battery, then each of them has the same voltage of the battery, but not the same current.
When two similar resistances are joined parallel to each other , current becomes two times . It is as per ohm's law. On joining in parallel two equal resistances , total resistances of circuit become half. Hence as per ohm's law , current becomes double. Hence the given resistance is ohmic.
Current through the battery will be same as external current in the circuit . Let it be I . Let the external resistance be R . Let the emf of the battery be E . Potential difference on the battery
ΔV = E - IR
If I increases ΔVdecreases . So there is inverse relation.
Option D is correct .
So option A and D are correct.
If we have two or more components in series, the current that flows through each of them is the same.
In this case, the battery generates the current, and since there must be conservation of electric charge, no current can be lost through the resistors.
C.The current in the battery and in each resistor is the same.
In fact, when resistors are connected in series, the current flowing through them is the same in each resistor. This is also equal to the current flowing in the circuit, so it is the same as the current flowing through the battery.
In a series circuit, the value of the equivalent resistance is equal to the sum of the values of each of them:
Where:The equivalent resistance of the combination of resistors is greater than the resistance of any one of three resistors.
In this case the current flowing through the resistors is the same in each one. This is because the current flowing through the circuit only has one way to go, so the current intensity is the same throughout the circuit.
Therefore:The current flowing through each of the resistors is the same and is equal to the current through the battery. The algebraic sum of the voltages across the three resistors is equal to the voltage across the battery.
The battery provides a voltage that is the sum of the different voltages at the ends of the resistors:
Where the Voltage, according to Ohm's law is:
Hence, the second statement of this question is True