The base of a 50-meter tower is at the origin; the base of a 50-meter tree is at (0, 50, 0). the ground is flat and the z-axis points upward. the following parametric equations describe the motion of six projectiles each launched at time t = 0 in seconds. (i) r (t) = (50 + t2)k (ii) r (t) = 2t2 j + 2t2k (iii) r (t) = 50 i + 50 j + (50 − t2)k (iv) r (t) = 2t j + (50 − t2)k (v) r (t) = (50 − 2t) i + 2t j + (50 − t)k (vi) r (t) = t i + t j + tk (a) which projectile is launched from the top of the tower and goes downward? at time t = , the projectile hits the ground at point (x, y, z) = . (b) which projectile hits the top of the tree?
i wish i was smart
It seems that 1 might be A or B and 2 might be C or D. Hope this helps. :-)
Since the 4th root of 50 is 50^1/4, and (50^1/4)^4=1, raising the 4th root of 50 to the 4th power cancels the root and the power.
The root of a term is the 1/(that number) version of that term. Therefore, something that is a 4th root, must be that number raised to 1/4