During takeoff, an airplane climbs with a speed of 150 m/s at an angle of 45 degrees above the horizontal. the speed and direction of the airplane constitute a vector quantity known as the velocity. the sun is shining directly overhead. how fast is the shadow of the plane moving along the ground

106.1 m/s

Explanation:

The shadow of the plane is moving at the same velocity as the horizontal component of the airplane's velocity.

The horizontal component of the airplane's velocity is

where

v = 150 m/s is the velocity of the airplane

is the angle between the airplane's velocity and the horizontal

Substituting,

So, the shadow is moving at 106.1 m/s as well.

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the components of a vector are the parts of the vectors that are to each other.

b perpendicular