The two i-beams are welded together and are initially supported by the three cables of equal length hanging vertically from supports directly above a, b, and c. when applied with the appropriate offset d, the 200-n force causes the system to assume the new equilibrium configuration shown. all three cables are inclined at the same angle θ from the vertical, in planes parallel to the y-z plane. determine this deflection θ and the proper offset d. beams ab and oc have masses of 69 kg and 46 kg, respectively. the mass center of beam oc has a y-coordinate of 785 mm, beam ab is uniform.

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Answer body lying face up ;

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j