Air of 15 °c and 1.0 atm and is moving with a uniform velocity of 15.2 m/s and this flow is laminar. then, a thin sheet of naphthalene 0.254 cm thick and 10.2 cm square is placed in the air stream parallel to the direction of flow (air flows above and below the sheet). for how long, in hours, must the sheet be exposed to the air stream before one-tenth of its mass will have sublimed? assume the upper and lower surfaces remain flat at all times. the molecular diffusion coefficient for the air-naphthalene system is 185 cm2/h and the schmidt number is 2.57 under the conditions given in the problem. the vapor pressure of naphthalene at 15 °c is 0.0364 mmhg. neglect sublimation from the edges. the kinematic viscosity of air can be assumed to be 13.28 x 10-6 m2/s. the density of naphthalene is 1152 kg/m3. note: the transition to turbulent flow for this system occurs at rex = 3.0 x 105 so this should be checked