Question part points submissions used a car is traveling at 53.0 km/h on a flat highway. (a) if the coefficient of friction between road and tires on a rainy day is 0.115, what is the minimum distance in which the car will stop? incorrect: your answer is incorrect. m (b) what is the stopping distance when the surface is dry and the coefficient of friction is 0.575? m

(a) 95.9 m

The initial velocity of the car is

The car moves by uniformly accelerated motion, so we can use the SUVAT equation:

where

v = 0 is the final velocity

d is the stopping distance of the car

a is the acceleration of the car

The force of friction against the car is

where

is the coefficient of friction

m is the mass of the car

is the acceleration due to gravity

According to Newton's second law, the acceleration is

Substituting into the previous equation:

and solving for d:

(b) 19.1 m

This time, the coefficient of friction is

So the acceleration due to friction is:

And substituting into the SUVAT equation:

we can find the new stopping distance:

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2