Physics, 24.06.2019 19:50 scasemere

You have landed on an unknown planet, newtonia, and want to know what objects will weigh there. you find that when a certain tool is pushed on a frictionless horizontal surface by a 12.2 n force, it moves 16.1 m in the first 2.40 s , starting from rest. you next observe that if you release this tool from rest at 11.0 m above the ground, it takes 2.58 s to reach the ground. what does the tool weigh on newtonia? what would it weigh on earth?

Answers: 3

Show answers

Answers

Answer from: depaze6652

1. On Newtonia: 28.846N 2. On Earth:42.767N

Explanation:

The weight is the force with which a planet attracts an object with mass , due to the acceleration of gravity of said planet, and is given by the following equation:

W=m.g (1)

Knowing this, let's find the weight of an object on Newtonia and on Earth:

1. On Newtonia:

The weight in this planet is given by (1):

$W_{N}=m.g_{N}$ (2)

In addition, we are told that when a certain tool is pushed on a frictionless horizontal surface by a 12.2 N force, it moves 16.1 m in the first 2.40 s , starting from rest ( $X_{o}=0$ , $V_{o}=0$ and $t_{o}=0$ ).

By Newton's 2nd law of motion we know the force is given by:

F=m.a (3) Being the mass of the object and its acceleration.

Isolating : $m=\frac{F}{a}$ (4)

We already know F=12.2N , we need to find . In order to approach it, we will use the following equations related to the motion in one dimension:

$V=\frac{\Delta X}{\Delta t}=\frac{X-X_{o}}{t-t_{o}}$ (5)

$V=V_{o}+a.t$ (6)

From (5):

$V=\frac{16.1m-0}{2.40s-0}=6.708m/s$ (7)

Substituting (7) in (6):

6.708m/s=0+a(2.40s) (8)

Finding : $a=\frac{6.708m/s}{2.40s}=2.795m/s^{2}$ (9)

Substituting (9) in (4):

$m=\frac{12.2n}{2.795m/s^{2}}$ (10)

m=4.364kg (11)

On the other hand, we are told that if you release this tool from rest ( $V_{oy}=0$ and $t_{o}=0$ ) at y=11.0m above the ground, it takes t=2.58s to reach the ground.

In this case we will use the following equation:

$y=V_{oy}.t-\frac{1}{2}g_{N}.t^{2}$ (12)

$11m=0-\frac{1}{2}g_{N}(2.58s)^{2}$ (13)

Finding $g_{N}$ :

$g_{N}=-6.610m/s^{2}$ (14) Where the negative sign only indicates the acceleration is "downwards", to the center of the planet.

Substituting (14) in (1):

$W_{N}=(4.364kg)(6.610m/s^{2})$ (15)

$W_{N}=28.846N$ This is the weight of the tool on Newtonia.

2. On Earth:

In the case of our planet, we will use the same weight equation, knowing the acceleration due gravity on Earth is $g_{E}=9.8m/s^{2}$ :

$W_{E}=m.g_{E}$ (16)

$W_{E}=(4.364kg)(9.8mm/s^{2})$ (17)

Finally:

$W_{E}=42.767N$ This is the weight of the same tool on Earth.

Answer from: Quest

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

hope this ! this is not copied! search it up, it's free of plagiarism!

Answer from: Quest

that the claims meet official rules.

don't misinterpret the claims

Another question on Physics

Physics, 22.06.2019 10:30

J. j. thomson’s experiment disproved the theory that an atom

Answers: 3

Answer

Physics, 22.06.2019 12:10

Consider a one meter long horizontal pipe with a constant 100 cm^2 cross sectional area. water flows rightward into the pipe at x = 0 with flow velocity 02m/sec at every point within the pipe intake area. at x=1, the rightward flow rate is 0.192 m/sec. assume the water is a conserved quantity in the pipe, so there must be a leak (a sink) somewhere in the pipe. 1. compute net volumetric flow of the source if the system to be in equilibrium. 2. now assume the pipe in the problem has no leaks. compute the net volumetric rate of change for the system.

Answers: 3

Answer

Physics, 22.06.2019 13:40

What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wavelength of 480 ? the index of refraction of the film is 1.34, and there is air on both sides of the film. express your answer in nanometers. hint 1. how to approach th

Answers: 1

Answer

Physics, 22.06.2019 17:10

Which statement best describes the superposition principle? a.) if two in-phase waves arrive simultaneously at a point, their amplitudes add up b.) if two out-of-phase waves arrive simultaneously at a point, their amplitudes add up c.) if two in-phase waves arrive at a point one after another, their amplitudes add up d.) if two out-of-phase waves arrive at a point one after another, their amplitudes adds up

Answers: 2

Answer

You know the right answer?

You have landed on an unknown planet, newtonia, and want to know what objects will weigh there. you...

Questions